Reverse Linked List
Given a linked list (as comma-separated values), reverse it and return the reversed list.
Output as space-separated values.
Example:
1,2,3,4,5
5 4 3 2 1
- The input string "1,2,3,4,5" is split into individual node values: 1, 2, 3, 4, 5
- A linked list is created from these values, with each node pointing to the next one: 1→2→3→4→5
- The linked list is reversed by updating the pointers of each node to point to the previous node: 5→4→3→2→1
- The reversed linked list is then traversed to extract the node values in the reversed order: 5, 4, 3, 2, 1
- The final output is the reversed list as space-separated values: 5 4 3 2 1
Constraints:
- 0 <= number of nodes <= 5000
- -5000 <= Node.val <= 5000
Background Knowledge
The problem involves a linked list, which is a linear data structure where each element is a separate object, and each element (or "node") points to the next node in the sequence. This structure allows for efficient insertion and deletion of nodes at any position in the list. In the context of this problem, we're given a linked list as comma-separated values, which we'll need to reverse and return as space-separated values.
To tackle this problem, it's essential to understand the basics of node structure and pointer manipulation. In a linked list, each node typically has two components: a value (the data stored in the node) and a next pointer (a reference to the next node in the list). When reversing a linked list, we need to update the next pointers of each node to point to the previous node, effectively reversing the direction of the links.
Understanding the concept of iteration and recursion is also crucial, as these are common approaches used to traverse and manipulate linked lists. Iteration involves using a loop to traverse the list, while recursion involves using function calls to traverse the list. Both approaches have their trade-offs, and the choice of which to use depends on the specific problem requirements and constraints.
Algorithm/Approach
The general approach to solving this type of problem involves using a two-pointer technique or a recursive approach. The two-pointer technique involves using two pointers, one to keep track of the current node and another to keep track of the previous node, to reverse the links between nodes. The recursive approach involves using function calls to recursively traverse the list and reverse the links.
Step-by-Step Strategy
To implement the solution, follow these steps:
- Initialize a head pointer to the first node of the list
- Initialize a prev pointer to None
- Iterate through the list, updating the next pointer of each node to point to the previous node
- Keep track of the new head of the reversed list
- Return the reversed list as space-separated values
Common Pitfalls
When implementing the solution, watch out for:
- Losing track of the head of the reversed list
- Not updating the next pointers correctly
- Not handling the base case correctly (e.g., an empty list or a list with one node)
Time & Space Complexity
The expected time complexity for this problem is O(n), where n is the number of nodes in the list, since we need to traverse the entire list to reverse it. The expected space complexity is O(1), since we only need to use a constant amount of space to store the pointers and variables. However, if we use a recursive approach, the space complexity may be O(n) due to the recursive call stack.