Top K Frequent Elements
Given an integer array and integer k, return the k most frequent elements in any order.
Output space-separated, sorted.
Example:
1,1,1,2,2,3 2
1 2
- First, we count the frequency of each element in the array: 1 appears 3 times, 2 appears 2 times, and 3 appears 1 time.
- Then, we sort the elements by their frequency in descending order: 1 (3 times), 2 (2 times), 3 (1 time).
- Next, we select the top k=2 most frequent elements, which are 1 and 2.
- The final output is the selected elements in sorted order: 1 2
Constraints:
- 1 <= len(nums) <= 10^5
- 1 <= k <= number of unique elements
Background Knowledge
The "Top K Frequent Elements" problem involves finding the most frequent elements in an array. To solve this, it's essential to understand hash maps, which are data structures that store key-value pairs. In this context, we can use a hash map to count the frequency of each element in the array. The key concept here is that hash maps allow for efficient lookups, insertions, and deletions, with an average time complexity of O(1).
Another crucial concept is counting, which is a fundamental technique in algorithm design. Counting involves keeping track of the number of occurrences of each element in the array. This can be done using a hash map, where the keys are the elements and the values are their corresponding counts. Understanding how to iterate through the array, update the counts, and retrieve the top k elements is vital to solving this problem.
The problem also requires an understanding of sorting and priority queues, as we need to return the top k frequent elements in sorted order. However, since the problem statement allows for any order, we can focus on finding the top k elements first and then sorting them if necessary. The key idea is to use a data structure that allows us to efficiently extract the top k elements, such as a heap or a sorted array.
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