Remove Nth Node From End
Given an array representing a linked list and an integer n, remove the nth node from the end and return the modified list.
Output as space-separated integers, or empty if list becomes empty.
Example:
1,2,3,4,5 2
1 2 3 5
- The linked list is created from the input array: 1, 2, 3, 4, 5
- We need to remove the nth node from the end, where n=2, so we count from the end: 5 (1st), 4 (2nd)
- The 2nd node from the end is the one with value 4, which is removed from the list
- The modified list is then output as space-separated integers: 1, 2, 3, 5
Constraints:
- 1 <= len(list) <= 30
- 0 <= list[i] <= 100
- 1 <= n <= len(list)
Background Knowledge
The problem deals with linked lists, a fundamental data structure in computer science. A linked list is a sequence of nodes, where each node contains a value and a reference (i.e., a "link") to the next node in the sequence. This structure allows for efficient insertion and deletion of nodes at any position in the list. To solve this problem, you should be familiar with basic linked list operations, such as traversing the list and accessing node values.
In the context of linked lists, it's essential to understand the concept of node pointers. A node pointer is a reference to a specific node in the list. When you move a node pointer from one node to the next, you are essentially "traversing" the list. This concept is crucial for solving problems that involve modifying the list, such as removing a node. You should also be comfortable with the idea of node indices, which refer to the position of a node in the list (e.g., the first node is at index 0).
To remove the nth node from the end, you need to consider the list's length and how to efficiently locate the node to be removed. This involves understanding how to calculate the index of the node to be removed, given the list's length and the value of n. You may need to use mathematical concepts, such as n=len(list)−k, where k is the index of the node to be removed from the end.
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