First Unique Character in a String
Given a string s, find the first non-repeating character and return its index. Return -1 if no such character exists.
Example:
leetcode
0
- First, we count the frequency of each character in the string
s = leetcode. - Then, we iterate over the string to find the first character with a frequency of 1.
- We find that the character
lappears only once and it is the first character in the string, so its index is 0. - The final output is the index of the first non-repeating character, which is 0.
Constraints:
- 1 <= len(s) <= 10^5
- s consists of lowercase English letters
Background Knowledge
The problem "First Unique Character in a String" involves finding the first non-repeating character in a given string s. To approach this problem, it's essential to understand the concept of frequency counting, where we count the occurrence of each character in the string. This can be achieved using a hash table (or dictionary) to store the frequency of each character. The hash table allows for efficient lookups, insertions, and updates of character frequencies.
In the context of Streaming & Queues, this problem can be seen as a simple example of processing a stream of characters (the input string) and finding a specific character that meets a certain condition (being the first non-repeating character). Understanding how to process streams of data and use data structures like queues or hash tables is crucial for solving problems in this topic.
The problem also touches on the concept of indexing, where we need to keep track of the position of each character in the original string. This requires understanding how to iterate over the string, access characters by their index, and return the correct index of the first non-repeating character.
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