Counting Bits
Given an integer n, return an array of length n+1 where ans[i] is the number of 1s in the binary representation of i.
Example:
5
0 1 1 2 1 2
- The function generates an array of length n+1, where n is the input integer, so for n=5, the array will have 6 elements.
- It then iterates over each number i from 0 to n (inclusive), converting i to its binary representation and counting the number of 1s.
- The binary representations and their corresponding 1s counts are as follows:
- 010=02 (0 ones)
- 110=12 (1 one)
- 210=102 (1 one)
- 310=112 (2 ones)
- 410=1002 (1 one)
- 510=1012 (2 ones)
- The final output is an array containing these counts in order:
[0, 1, 1, 2, 1, 2].
Constraints:
- 0 <= n <= 10^5
Background Knowledge
The problem revolves around bit manipulation, which is a fundamental concept in computer science. In computer systems, information is represented as binary digits (bits) that can have a value of either 0 or 1. Binary representation of a number is a way of expressing that number using only these two digits. For example, the decimal number 5 is represented as 101 in binary. Understanding how to work with binary numbers, including how to count the number of 1s (also known as the Hamming weight), is crucial for solving this problem.
To approach this problem, one needs to have a basic understanding of how binary numbers work and how to manipulate them. This includes understanding bitwise operations such as shifting (left or right) and masking. However, for the specific task of counting the number of 1s in the binary representation of a number, there are efficient algorithms and techniques that can be applied. One key concept is the use of dynamic programming or iterative methods to efficiently compute the number of 1s for each number up to n.
The problem also touches on the idea of iterative computation, where the solution for one value is built upon the solution of previous values. This is a common pattern in algorithm design and can significantly reduce computational complexity by avoiding redundant calculations. By understanding these concepts, one can develop an efficient solution to the "Counting Bits" problem.
Algorithm/Approach
The general approach to solving this type of problem involves using an iterative method to calculate the number of 1s in the binary representation of each number from 0 to n. This can be achieved by either directly counting the bits for each number or by using a more efficient algorithm that leverages patterns in binary representations. One such pattern involves recognizing how the binary representation of numbers changes as you increment from one number to the next.
Step-by-Step Strategy
- Initialize an array ans of length n+1 to store the count of 1s for each number from 0 to n.
- Consider the base case (e.g., ans = 0 since the binary representation of 0 is 0, which has no 1s).
- Iterate through each number from 1 to n.
- For each number i, determine the number of 1s in its binary representation. This can be done through direct counting or by leveraging a pattern or property of binary numbers.
- Store the count of 1s for i in ans[i].
- After iterating through all numbers, ans will contain the desired counts.
Common Pitfalls
- Incorrectly handling the base case or edge cases (e.g., n = 0 or n = 1).
- Failing to consider the most efficient method for counting 1s in binary representations, potentially leading to an overly complex or inefficient solution.
- Not properly initializing the ans array or incorrectly indexing it.
Time & Space Complexity
- Time Complexity: The time complexity will depend on the method used to count the 1s in each binary representation. A naive approach could result in O(nlogn) time complexity if counting bits for each number individually, but more efficient algorithms can achieve O(n) time complexity.
- Space Complexity: The space complexity is primarily determined by the need to store the counts for each number from 0 to n, resulting in a space complexity of O(n).