Pinhole Camera Intrinsic Projection
Given a 3D point in camera coordinates and a camera intrinsic matrix K, compute the projected 2D pixel coordinates using the pinhole camera model.
The intrinsic matrix K has the form:
K=​fx​00​0fy​0​cx​cy​1​​
Where fx​,fy​ are focal lengths and (cx​,cy​) is the principal point.
The projection formula is:
​uv1​​=Zc​1​K​Xc​Yc​Zc​​​
Return the 2D pixel coordinates [u,v] rounded to 2 decimal places.
Example:
print(pinhole_projection([[800.0, 0.0, 320.0], [0.0, 800.0, 240.0], [0.0, 0.0, 1.0]], [10.0, 20.0, 5.0]))
[1920.0, 3440.0]
- Multiply K by the 3D point: Kâ‹…[100,50,10]T
- Divide by Zc​=10 to get normalized coordinates
- Result: [u,v]=[610.0,355.0]
Constraints:
- The input point w' = [u', v', w'] has depth w' > 0
- Lambda is a valid 3x3 intrinsic matrix
- All inputs are floating-point numbers
- Output must be rounded to 4 decimal places
1. Background Knowledge
The pinhole camera model is the foundational idealization in computer vision for perspective projection, assuming light rays pass through a single point (pinhole) to form an image on the sensor plane. Key concepts include:
- Camera coordinates: 3D point Pc​=[Xc​,Yc​,Zc​]T in the camera frame, where Zc​>0 is depth (behind the pinhole).
- Intrinsic matrix K: Encodes internal parameters—focal lengths fx​,fy​ (pixels per radian in x/y), principal point (cx​,cy​) (image center offset).
- Homogeneous coordinates: Enable perspective division; projection yields [u,v,1]T=\frac{1}{Z_c}KPc​, where pixel [u,v] is the normalized image point.
- Prerequisites: Matrix multiplication, perspective division, NumPy-like array operations. No distortion assumed here (ideal pinhole).
This model underpins tasks like 3D reconstruction and augmented reality.
2. Algorithm Approach
Direct matrix-vector multiplication followed by normalization:
- Compute intermediate homogeneous point: p′=KPc​.
- Apply perspective division: u=px′​/pz′​, v=py′​/pz′​.
Pseudocode:
import numpy as np
def project_point(Pc, K):
p_hom = K @ Pc # 3x3 @ 3x1 -> 3x1
u = p_hom / p_hom
v = p_hom / p_hom
return np.round([u, v], 4) # As per constraints
This is O(1) per point—pure linear algebra, no iteration or search.
3. Step-by-Step Strategy
- Parse inputs: Extract Pc​=[Xc​,Yc​,Zc​]T (3x1 vector), K (3x3 matrix). Verify Zc​>0.
- Matrix multiply: p′=K\mathbf{P_c}=​fx​Xc​+cx​Zc​fy​Yc​+cy​Zc​Zc​​​.
- Divide: u=p0′​/p2′​, v=p1′​/p2′​ (0-indexed).
- Round: To 4 decimal places (overrides description's 2).
- Return: [u,v].
Example (assume K=​80000​08000​3202401​​, Pc​=[1,0.5,2]T):
- p′=[800⋅1+320⋅2,800⋅0.5+240⋅2,2]=[1920,1360,2]
- [u,v]=[960.00,680.00]
4. Common Pitfalls
- No division by zero: Zc​>0 guaranteed, but floating-point underflow near zero causes NaN—add epsilon check (10−6).
- Matrix orientation: Ensure K row-major, Pc​ column vector (not row).
- Rounding mismatch: Use 4 decimals per constraints, not 2.
- Homogeneous scaling: Ignore overall scale; only divide x/y by z.
- Units: Inputs in pixels/meters consistently; no world-to-camera transform needed.
- Distortion ignored: Problem assumes ideal pinhole—real cameras need correction.
5. Time & Space Complexity
- Time: O(1) constant—9 multiplications + 4 additions + 2 divisions for matrix-vector product.
- Space: O(1) constant—stores one 3x1 vector and reuses K (3x3).
Full implementation (Python):
def pinhole_projection(Xc, Yc, Zc, fx, fy, cx, cy):
# Or parse full K matrix
u = (fx * Xc + cx * Zc) / Zc
v = (fy * Yc + cy * Zc) / Zc
return [round(u, 4), round(v, 4)]
This solves the problem directly while building intuition for camera geometry.