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Cylindrical Projection for Panoramas

hardFREEPanoramasWarpingCV: Image Alignment and Stitching

Implement cylindrical projection for 360° panorama stitching, a crucial step in image alignment and stitching that enables the creation of seamless panoramic images. This process involves mapping image coordinates to a cylinder, allowing for efficient stitching of multiple images.

The cylindrical projection is a geometric transformation that maps 2D image coordinates to a cylindrical surface, which is essential for 360° panorama stitching. The projection equations are given by x′=f⋅arctan⁡(x−cxf)x' = f \cdot \arctan(\frac{x - c_x}{f}) and y′=f⋅y−cy(x−cx)2+f2y' = f \cdot \frac{y - c_y}{\sqrt{(x - c_x)^2 + f^2}}, where ff is the focal length and (cx,cy)(c_x, c_y) is the image center.

Here are the steps to achieve this projection:

  1. Define the input image coordinates (x,y)(x, y) and the focal length ff.
  2. Calculate the image center (cx,cy)(c_x, c_y).
  3. Apply the cylindrical projection equations to obtain the projected coordinates (x′,y′)(x', y').
x′=f⋅arctan⁡(x−cxf)x' = f \cdot \arctan(\frac{x - c_x}{f}) y′=f⋅y−cy(x−cx)2+f2y' = f \cdot \frac{y - c_y}{\sqrt{(x - c_x)^2 + f^2}}

Output format: return an image of the same size (H,W)(H, W) as the input, with values as unsigned 8-bit integers. The projected coordinates are re-centred on the image, so a source pixel lands at column x′+cxx' + c_x and row y′+cyy' + c_y (the image center stays where it is). Use cx=W/2c_x = W/2, cy=H/2c_y = H/2. Output pixels that receive no part of the source image are 00.

This technique is widely used in virtual reality and computer vision applications.

Example

Input
image = 1000×1000 image
focal_length = 500
Output
Cylindrically warped image (curved edges)
Reasoning
  • Inputs: image is a 1000×10001000 \times 1000 grid of intensities and focal_length f=500f = 500 pixels, so the center is (cx,cy)=(500,500)(c_x, c_y) = (500, 500).
  • Center: a pixel at x−cx=0x - c_x = 0 has x′=farctan⁡0=0x' = f \arctan 0 = 0 and y′=y−cyy' = y - c_y, so the middle column is untouched and keeps its full height of 10001000 rows.
  • Left/right edges: the source edge x−cx=499x - c_x = 499 maps to x′=500arctan⁡499500≈392.2x' = 500 \arctan \tfrac{499}{500} \approx 392.2. The 10001000-pixel width shrinks to roughly columns 108108 to 892892; everything outside is 00.
  • Top/bottom edges: at that edge the vertical factor is 5004992+5002≈0.708\frac{500}{\sqrt{499^2 + 500^2}} \approx 0.708, so the ±500\pm 500 rows squeeze to about ±354\pm 354 (rows 146146 to 853853 in column 892892).
  • Output: a 1000×10001000 \times 1000 cylindrically warped image (curved edges): full height in the middle, shorter toward the sides. Notice arctan⁡\arctan barely changes small offsets but compresses large ones; a larger ff flattens the curve.

Constraints

  • image: Input image (H, W)
  • focal_length: Camera focal length in pixels
  • Return: Cylindrically projected image

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solution.py

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