Calculate Output Volume
Problem Statement
Calculate the spatial dimensions of a convolutional layer output.
Background
The output size O of a convolutional layer is determined by input size I, filter size F, padding P, and stride S using the formula:
O=⌊SI−F+2P​⌋+1
If the filter is larger than the padded input (i.e., I−F+2P<0), the configuration is invalid.
Your Task
Write a function conv_output_size(input_size, filter_size, padding, stride) that returns the output dimension. If the configuration is invalid (filter larger than padded input), return -1.
Output Format
Return an integer representing the output dimension, or -1 if invalid.
Example:
input_size=32, filter_size=3, padding=1, stride=1
32
floor((32 - 3 + 2*1) / 1) + 1 = floor(32/1) + 1 = 32
Constraints:
- 1 <= input_size <= 1000
- 1 <= filter_size <= input_size
- 0 <= padding <= 100
- 1 <= stride <= input_size
1. Background Knowledge
Convolutional layers are core components of Convolutional Neural Networks (CNNs), which process grid-like data (e.g., images) by sliding filters (kernels) over the input to extract features. Key parameters affecting output size:
- Input size (I): Spatial dimension of input feature map (e.g., height/width).
- Filter size (F): Dimension of the kernel (e.g., 3×3).
- Padding (P): Zero-padding added to input borders (expands effective input to I+2P).
- Stride (S): Step size for sliding the filter.
The standard formula for 1D/2D output size O (applied independently per dimension) is:
O=⌊SI−F+2P​⌋+1This derives from counting valid filter positions: the filter needs F input positions, padded input provides I+2P, and stride S determines output steps. If I−F+2P<0, no valid positions exist (invalid config).
Prerequisites: Basic CNN architecture (conv → activation → pool), integer division/flooring in programming, and understanding CNNs process spatial hierarchies.
2. Algorithm Approach
This is a direct formula evaluation problem—no search/training needed. Common techniques:
- Exact computation: Plug values into the formula with floor division.
- Validity check: Pre-validate I+2P≥F (equivalent to I−F+2P≥0) to return -1 early.
- Vectorized extension (for multi-dim): Apply per axis (height/width) for 2D conv, but here it's 1D scalar.
No iterative algorithms (e.g., Winograd/FFT for fast conv ) apply—pure arithmetic.
3. Step-by-Step Strategy
- Validate inputs (optional, per constraints): Ensure 1≤I,F,S≤1000, 0≤P≤100, F≤I.
- Compute padded size: padded = I + 2 * P.
- Check validity: If padded < F, return -1.
- Calculate core expression: numerator = padded - F, then output = floor(numerator / S) + 1.
- Return result: Integer output size.
Python Implementation:
def conv_output_size(input_size, filter_size, padding, stride):
padded = input_size + 2 * padding
if padded < filter_size:
return -1
numerator = padded - filter_size
output = (numerator // stride) + 1 # Floor division via //
return output
Verification (sample): I=32,F=3,P=1,S=1 → padded=34 ≥3, (34-3)/1=31, floor(31)+1=32 ✓.
4. Common Pitfalls
- Off-by-one errors: Forgetting +1 or mishandling floor (use // in Python, not /).
- Invalid config mischeck: Testing I<F ignores padding—must use I+2P<F.
- Floating-point division: numerator / S may yield float; always floor explicitly.
- Negative numerator: Floor of negative (e.g., Python (-1)//2 = -1)—but validity check prevents.
- 2D confusion: Problem is 1D (scalar return); don't assume H/W pair.
- Edge cases: S=1,P=0,F=I → O=1; P=0,F=I+1 → -1; S>I → often 1 or -1.
Test edges: conv_output_size(1,1,0,1) →1; conv_output_size(5,7,1,1) →-1.
5. Time & Space Complexity
- Time: O(1)—constant arithmetic operations, independent of input sizes.
- Space: O(1)—few scalar variables, no arrays/structures.
Optimal for real-time CNN design tools; scales to batched/3D conv by vectorization (still O(1) per dim).