Diagonal Traverse
Given an m x n matrix, return all elements in diagonal order (alternating up-right and down-left).
Output space-separated.
Example:
1,2,3 4,5,6 7,8,9
1 2 4 7 5 3 6 8 9
- The input matrix is traversed in diagonal order, starting from the top-left corner and alternating between up-right and down-left directions.
- The first diagonal consists of a single element: 1.
- The next diagonal consists of elements 2 and 4, and then 7 is added as it is the next element in the down-left diagonal.
- The following diagonals are traversed in the same manner, resulting in the sequence 1,2,4,7,5,3,6,8,9.
- The final output is the space-separated sequence of elements in diagonal order: 124753689
Constraints:
- 1 <= m, n <= 10^4
- 1 <= m * n <= 10^4
Background Knowledge
The problem of "Diagonal Traverse" involves traversing a 2D matrix in a diagonal order, which alternates between up-right and down-left directions. To understand this problem, it's essential to have a solid grasp of matrix operations and array indexing. In a 2D matrix, each element is identified by its row and column indices. The diagonal order traversal requires navigating through the matrix in a way that visits elements in a diagonal pattern.
Key concepts to understand include matrix representation, where a matrix is represented as a collection of rows and columns, and indexing, which refers to accessing specific elements within the matrix using their row and column indices. Additionally, understanding the difference between row-major and column-major ordering is crucial, as it affects how elements are stored and accessed in the matrix.
In the context of diagonal order traversal, it's essential to recognize that the diagonal pattern can start from the top-left corner and move down-right or start from the top-right corner and move down-left. The problem requires alternating between these two diagonal directions, which involves careful management of row and column indices to ensure correct traversal.
Algorithm/Approach
The algorithmic approach to solving this problem involves using a combination of looping constructs and conditional statements to navigate the matrix in a diagonal order. The general pattern involves iterating over the matrix elements, using the row and column indices to determine the current diagonal direction, and adjusting the indices accordingly to move to the next element in the diagonal order.
Step-by-Step Strategy
To implement the solution, follow these steps:
- Initialize variables to keep track of the current row and column indices.
- Determine the starting point of the diagonal traversal (e.g., top-left or top-right corner).
- Use a looping construct to iterate over the matrix elements, adjusting the row and column indices based on the current diagonal direction.
- Use conditional statements to alternate between up-right and down-left diagonal directions.
- Store the visited elements in a data structure (e.g., array or list) to output the diagonal order.
Common Pitfalls
When implementing the solution, watch out for:
- Incorrect indexing or bounds checking, which can lead to index out of range errors.
- Failure to alternate between diagonal directions, resulting in an incorrect traversal order.
- Inefficient use of data structures or looping constructs, which can impact performance.
Time & Space Complexity
The expected time complexity for this problem is O(mâ‹…n), where m and n are the dimensions of the input matrix, since we need to visit each element once. The space complexity is also O(mâ‹…n), as we need to store the visited elements in a data structure. However, the actual space complexity may vary depending on the specific implementation and data structures used.