Nested List Weight Sum
Given a nested list of integers, return the sum where each integer is multiplied by its depth. The outermost list is depth 1.
Input: nested list as JSON string.
Example:
[[1,1],2,[1,1]]
10
- The input
[[1,1],2,[1,1]]is a nested list with integers at different depths. - We calculate the weighted sum by multiplying each integer by its depth:
- The inner lists
[1,1]are at depth 2, so their integers contribute 1â‹…2+1â‹…2=4 each. - The integer
2is at depth 1, so it contributes 2â‹…1=2. - The last inner list
[1,1]is also at depth 2, contributing another 1â‹…2+1â‹…2=4.
- The inner lists
- The total sum is then calculated as 4+2+4=10.
- The final output is 10.
Constraints:
- 1 <= total elements <= 50
- Nesting depth <= 50
- -100 <= integer value <= 100
Background Knowledge
The problem involves working with nested lists, which are lists that contain other lists as elements. This type of data structure can be challenging to work with, especially when trying to access or manipulate elements at different depths. To tackle this problem, it's essential to understand how to iterate over nested lists and how to keep track of the current depth.
In computer science, recursion is a fundamental concept that can be used to solve problems involving nested structures. Recursion involves breaking down a problem into smaller sub-problems of the same type, which can be solved using the same approach. In the context of nested lists, recursion can be used to iterate over each element, checking if it's a list or an integer, and then recursively processing the sublist if necessary.
Another crucial concept is depth-first search (DFS), which is a traversal approach that explores a graph or tree data structure by visiting a node and then visiting all of its neighbors before backtracking. In the case of nested lists, DFS can be used to iterate over each element, keeping track of the current depth, and calculating the weighted sum.
Algorithm/Approach
The algorithm pattern that can be applied to this problem is a variation of depth-first search (DFS). The approach involves iterating over each element in the nested list, checking if it's a list or an integer, and then recursively processing the sublist if necessary. The key insight is to keep track of the current depth and use it to calculate the weighted sum.
Step-by-Step Strategy
To solve this problem, follow these steps:
- Initialize a variable to store the sum of the weighted integers
- Define a recursive function that takes a nested list and the current depth as arguments
- In the recursive function, iterate over each element in the list
- If the element is an integer, add its weighted value to the sum (i.e., multiply it by the current depth)
- If the element is a list, recursively call the function with the sublist and the current depth + 1
- After iterating over all elements, return the sum
Common Pitfalls
When implementing the solution, watch out for the following common pitfalls:
- Forgetting to update the depth when recursively calling the function
- Not handling the base case correctly (i.e., when the input list is empty)
- Not initializing the sum variable correctly
Time & Space Complexity
The expected time complexity for this problem is O(n), where n is the total number of integers in the nested list, since we need to visit each element once. The space complexity is O(d), where d is the maximum depth of the nested list, since we need to store the recursive call stack. However, in the worst-case scenario, the space complexity can be O(n) if the nested list is highly unbalanced.