Min Cost Climbing Stairs
Given an array cost where cost[i] is the cost of the ith step, you can start from step 0 or 1. Each step you can climb 1 or 2 steps. Return the minimum cost to reach the top (past the last step).
Example:
10,15,20
15
- We start by initializing an array
dpwheredp[i]represents the minimum cost to reach the ith step. For the given input,cost = [10, 15, 20], we havedp[0] = 10anddp[1] = 15. - Then, we fill up the
dparray by iterating through thecostarray. For each stepi, we calculatedp[i] = min(dp[i-1], dp[i-2]) + cost[i]. So,dp[2] = min(dp[1], dp[0]) + cost[2] = min(15, 10) + 20 = 10 + 20 = 30. - However, since we can start from step 0 or 1 and climb 1 or 2 steps, we consider the minimum cost to reach the top as
min(dp[n-1], dp[n-2]), wherenis the number of steps. In this case,min(dp[2], dp[1]) = min(30, 15) = 15. - The final output is the minimum cost to reach the top, which is 15.
Constraints:
- 2 <= len(cost) <= 1000
- 0 <= cost[i] <= 999
Background Knowledge
The "Min Cost Climbing Stairs" problem is a classic example of a Dynamic Programming problem. Dynamic Programming is a method for solving complex problems by breaking them down into simpler subproblems, solving each subproblem only once, and storing the solutions to subproblems to avoid redundant computation. This approach is particularly useful for problems that have overlapping subproblems or optimal substructure, meaning that the problem can be broken down into smaller subproblems, and the optimal solution to the larger problem can be constructed from the optimal solutions of the subproblems.
In the context of the "Min Cost Climbing Stairs" problem, we can think of each step as a subproblem, and the minimum cost to reach each step as the solution to that subproblem. We can use Dynamic Programming to build up a solution to the larger problem by solving each subproblem and storing the results. The key concept here is to recognize that the minimum cost to reach a given step depends on the minimum cost to reach the previous steps, which is a hallmark of a Dynamic Programming problem.
The optimal substructure of the problem is also important to recognize. In this case, the optimal substructure is the fact that the minimum cost to reach the top of the stairs can be constructed from the minimum costs to reach the previous steps. This means that we can focus on finding the minimum cost to reach each step, and then use those results to find the minimum cost to reach the top of the stairs.
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